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Mysql BETWEEN clause being ignored. No syntax error


Mysql BETWEEN clause being ignored. No syntax error

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Mysql BETWEEN clause being ignored. No syntax error
Tag : php , By : Vitalik
Date : January 10 2021, 01:47 PM


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Mysql like clause throwing syntax error?


Tag : mysql , By : anon
Date : March 29 2020, 07:55 AM
will be helpful for those in need Sql statements use single quotes around literal values. Also only one where clause is needed in this case. Simply use one where clause and then use or to connect the predicates. The script also has some parenthesis that are not required.
The final result looks like:
SELECT * FROM `videos` WHERE
    `videos`.`title` LIKE '%apple%' OR 
    `videos`.`byline` LIKE '%apple%' OR 
    `videos`.`description` LIKE '%apple%';

Error in MySQL Syntax with WHERE clause


Tag : php , By : Al Dimond
Date : March 29 2020, 07:55 AM
this will help could you check and tell me where i have made a mistake? Here is the code: , Clause order is incorrect : WHERE -> ORDER -> LIMIT :
$sql = "SELECT prekės.*
             , CONCAT(vartotojai.name) as v_name
        FROM prekės LEFT JOIN vartotojai ON vartotojai.V_ID=prekės.V_ID
        WHERE prekės.category='Telefonai'
        ORDER BY prekės.date
        LIMIT $offset, $rec_limit
       ";

mysql where clause syntax error prestashop


Tag : php , By : WuJanJai
Date : March 29 2020, 07:55 AM
this one helps. I am trying to list orders based on delivery country. For that purpose I have written sql query below. It works fine on database. But when i try to implement on AdminOrderController.php file, it throws syntax error which i tried to solve in many ways by changing syntax. , Solution:
$this->_where = 'AND country_lang.id_country = 8';

MYSQL where clause causes syntax error


Tag : mysql , By : Enrique Anaya
Date : March 29 2020, 07:55 AM
To fix the issue you can do GROUP is a reserved word so it needs to be between back tick `` Also, if $galgroup can be a string and not only a number, you need to add quotes arround it :
$stat_qry = mysql_query("SELECT * FROM stats WHERE `group`='$galgroup'") or 
die("STATS ERROR: ".mysql_error()); $stat = mysql_fetch_array($stat_qry);

if statement in where clause mysql syntax error


Tag : php , By : richardD
Date : March 29 2020, 07:55 AM
Does that help If I understand correctly you want to have a dynamic query based on the whether the testcase value is set or not?
If that is the case you can try this:
if(isset($_POST['Submit'])) {
$branch = $_POST['branch'];
$testcase = "";

 if (isset($_POST['testcase'])) {
    $testcase = "and testcase like '" . $_POST['testcase'] . "'";
 }

 $query = "SELECT * FROM table
 WHERE branch='$branch' $testcase";
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