How to find out how namespace got polluted?

How to find out how namespace got polluted?

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How to find out how namespace got polluted?
Tag : cpp , By : bikefixxer
Date : January 02 2021, 06:48 AM

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What does it mean global namespace would be polluted?

Tag : javascript , By : user183526
Date : March 29 2020, 07:55 AM
like below fixes the issue Quick Note On Garbage Collection
As variables lose scope, they will be eligible for garbage collection. If they are scoped globally, then they will not be eligible for collection until the global namespace loses scope.
var arra = [];
for (var i = 0; i < 2003000; i++) {
 arra.push(i * i + i);
 var arra = [];
 for (var i = 0; i < 2003000; i++) {
  arra.push(i * i + i);
var x1 = 5;
var x2 = 20;
var y1 = 3
var y2 = 16;

var rise = y2 - y1;
var run = x2 - x1;

var slope = rise / run;

var risesquared = rise * rise;
var runsquared = run * run;

var distancesquared = risesquared + runsquared;

var distance = Math.sqrt(dinstancesquared);
//Calculate is the only exposed global variable
var Calculate = function () {
 //all defintions in this closure are local, and will not be exposed to the global namespace
 var Coordinates = [];//array for coordinates
 var Coordinate = function (xcoord, ycoord) {//definition for type Coordinate
   this.x = xcoord;//assign values similar to a constructor
   this.y = ycoord;

  return {//these methods will be exposed through the Calculate object
   AddCoordinate: function (x, y) {
   Coordinates.push(new Coordinate(x, y));//Add a new coordinate

  Slope: function () {//Calculates slope and returns the value
   var c1 = Coordinates[0];
   var c2 = Coordinates[1];
   return c2.y - c1.y / c2.x - c1.x;//calculates rise over run and returns result

  Distance: function () {
   //even with an excessive amount of variables declared, these are all still local
   var c1 = Coordinates[0];
   var c2 = Coordinates[1];

   var rise = c2.y - c1.y;
   var run = c2.x - c1.x;

   var risesquared = rise * rise;
   var runsquared = run * run;

   var distancesquared = risesquared + runsquared;

   var distance = Math.sqrt(distancesquared);

   return distance;

//this is a "self executing closure" and is used because these variables will be
//scoped to the function, and will not be available globally nor will they collide
//with any variable names in the global namespace
(function () {
 var calc = Calculate();
 calc.AddCoordinate(5, 20);
 calc.AddCoordinate(3, 16);

Is javascript namespace polluted?

Tag : javascript , By : Pat
Date : March 29 2020, 07:55 AM
will help you Your while loop runs infinitely on the third pass because it doesn't meet the condition.

C++ redefinition of variable, global namespace polluted and I don't know why

Tag : cpp , By : alexmajy
Date : March 29 2020, 07:55 AM
around this issue time() is a function in standard C, which means that it's living outside a namespace so that "old" C code can be compiled with C++ compilers without having lots of using namespace std thrown in all over the place.
The header time.h is apparently included when you include , which is why you get a reference to that.
#pragma GCC system_header

#include <bits/c++config.h>
#include <time.h>

#define _GLIBCXX_CTIME 1

namespace std
  using ::time;
} // namespace

Package's namespace polluted by Django?

Tag : python , By : fukas78
Date : March 29 2020, 07:55 AM
hop of those help? This is normal Python behaviour.
When you import a submodule, that submodule is set as an attribute on the parent module. In this case, when simplelib.models is imported, the models submodule is set on the parent module simplelib. The parent module namespace is the same as that module's __init__.py global namespace. This will overwrite the old value.

Python __init__.py, less polluted namespace

Tag : python , By : Singularity
Date : March 29 2020, 07:55 AM
hop of those help? This behaviour is documented in chapter 5 of the Python Language Reference. If you really want to disable it, you can do this in __init__.py:
from .baz import do_something
del baz
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