Why does this B+ tree have repeated elements?

Why does this B+ tree have repeated elements?

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Why does this B+ tree have repeated elements?
Tag : development , By : desmiserables
Date : January 02 2021, 06:48 AM

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ListView Shows Repeated Elements When the Underlying Generic List Does Not Contain Repeated Elements

Tag : chash , By : user123284
Date : March 29 2020, 07:55 AM
Does that help Could you put some more code up? Perhaps you are using some reference variables that are using the same memory location? It's hard to tell with the code you uploaded.

Primefaces - Tree Component - Endless loop with repeated calls to recursive tree construction algorithm

Tag : java , By : liquidx
Date : March 29 2020, 07:55 AM
will be helpful for those in need Mea culpa! I have traced the problem down to a live lock introduced due to inappropriate usage of a static variable. Primefaces and JSF are not to blame for incorrect behaviour! Sorry for any inconvenience caused!

boost property_tree: iterating through attributes of repeated child elements within repeated child elements

Tag : xml , By : wrb302
Date : March 29 2020, 07:55 AM
wish helps you Attributes in property tree are added as sub-nodes. Below node can be translated
  <scenario name="ScenarioA">
    <param name="ParamA">1</param>
    <param name="ParamB">2</param>
    <param name="ParamC">3</param>
     xmlattr.name   ScenarioA // this node doesn't have subnode with attribute name
       xmlattr.name  -> ParamA
       xmlattr.name  -> ParamB
       xmlattr.name  -> ParamC
boost::property_tree::ptree scenarioTree = pt.get_child("root");
for (const auto& itr : scenarioTree) 
    if (itr.second.get<std::string>("<xmlattr>.name") == "ScenarioA") 
        boost::property_tree::ptree paramTree = itr.second;
        for (const auto& paramItr: paramTree) 
            if (paramItr.second.get<std::string>("<xmlattr>.name","") == "ParamA") 
            {                                                    ^^^^ default value
                cout << "ParamA was found in ScenarioA" << endl;

Remove or change SPECIFIC repeated elements of a list (not all repeated elements)

Tag : python , By : James B
Date : March 29 2020, 07:55 AM
I hope this helps . Use set:
lst = ["code", "this", "code"]
for elem in sorted(set(lst), key = lambda x:lst.index(x)):
    print(f"{elem} is repeated {lst.count(elem)} times")
for elem in dict.fromkeys(lst):
    print(f"{elem} is repeated {lst.count(elem)} times")
code is repeated 2 times
this is repeated 1 times
from collections import Counter
frequency = Counter(lst)
for word, freq in frequency.items():
    print(f"{word} is repeated {freq} times")
lst = ['code', 'this', 'code']
i = 0
while any(lst):
    if lst[i] == None:
        i += 1
    print(f"{lst[i]} is repeated {lst.count(lst[i])} times")
    lst = [None if j == lst[i] else j for j in lst]
    i += 1

how to get a non repeated element in scala val ele = List (1,2,3,4,2,3,5,6) output(1,4,5,6) only non repeated elements

Tag : scala , By : user181706
Date : September 22 2020, 11:00 AM
This might help you Explained differently, you want to filter elements for which the count of their occurences is only one.
Luckily, scala provides function for both those keywords !
val list = List(1, 2, 3, 4, 2, 3, 5, 6)
val result = list.filter(element => list.count(_ == element) == 1)
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