Comparation in JNI

Comparation in JNI

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Comparation in JNI
Tag : cpp , By : user187383
Date : January 02 2021, 06:48 AM

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binary comparation

Tag : cpp , By : Randoa
Date : March 29 2020, 07:55 AM
should help you out You can find the number of different bits by counting the bits in the xor of the two numbers. Something like this.
int count_bits(unsigned int n) {
    int result = 0;
    while(n) {
        result += 1;
        // Remove the lowest bit.
        n &= n - 1;
    return result;

int diff(unsigned int a, unsigned int b) {
    return count_bits(a ^ b);

Byte comparation

Tag : assembly , By : Martin Kopp
Date : March 29 2020, 07:55 AM
it fixes the issue byte ptr is MASM syntax. With NASM it should simply be byte, so your first example should be cmp byte [129],0 (see e.g. this syntax guide).

SortedSet<>.Contains() how to implement own comparation?

Tag : chash , By : Star Gryphon
Date : March 29 2020, 07:55 AM
this will help You have two options, create a class that implements IComparer (you should do IEqualityComparer too) and pass that in to the constructor of the sorted set.
public class NodeComparer : IComparer<Node>, IEqualityComparer<Node>
    public int Compare(Node node1, Node node2)
        //Sorts by X then by Y

        //perform the X comparison
        var result = node1.X.CompareTo(node2.X);
        if (result != 0)
            return result;

        //Perform the Y Comparison
        return node1.Y.CompareTo(node2.Y);

    public bool Equals(Node x, Node y)
        if (ReferenceEquals(x, y)) return true;
        if (ReferenceEquals(x, null)) return false;
        if (ReferenceEquals(y, null)) return false;
        if (x.GetType() != y.GetType()) return false;
        return x.X == y.X && x.Y == y.Y && x.rand == y.rand;

    public int GetHashCode(Node obj)
            var hashCode = obj.X;
            hashCode = (hashCode * 397) ^ obj.Y;
            hashCode = (hashCode * 397) ^ obj.rand;
            return hashCode;

public class Node
    public int X, Y;
    public int rand;

    public Node(int x, int y, int r)
    { X = x; Y = y; rand = r; }

class Program
    static void Main(string[] args)
        SortedSet<Node> mySet = new SortedSet<Node>(new NodeComparer());
        mySet.Add(new Node(1, 2, 90));
        Node myNode = new Node(1, 2, 50);
        // I want this to check if X and Y are the same
        if (mySet.Contains(myNode, interfaceThing))
            Console.WriteLine("Sth is already on that (X, Y) position");      
public class Node : IEquatable<Node>, IComparable<Node>
    public int X, Y;

    public int rand;

    public Node(int x, int y, int r)
    { X = x; Y = y; rand = r; }

    public bool Equals(Node other)
        if (ReferenceEquals(null, other)) return false;
        if (ReferenceEquals(this, other)) return true;
        return X == other.X && Y == other.Y && rand == other.rand;

    public override bool Equals(object obj)
        if (ReferenceEquals(null, obj)) return false;
        if (ReferenceEquals(this, obj)) return true;
        if (obj.GetType() != this.GetType()) return false;
        return Equals((Node)obj);

    public override int GetHashCode()
            var hashCode = X;
            hashCode = (hashCode*397) ^ Y;
            hashCode = (hashCode*397) ^ rand;
            return hashCode;

    public int CompareTo(Node other)
        //First order by X then order by Y then order by rand

        var result = X.CompareTo(other.X);
        if (result != 0)
            return result;

        result = Y.CompareTo(other.Y);
        if (result != 0)
            return result;

        return rand.CompareTo(other.rand);

Sorting arraylist. Comparation by int value

Tag : java , By : Robert M
Date : March 29 2020, 07:55 AM
this one helps. I'd like to sort my Listview by int value. I've looked in similar questions and solutions and have done something like this but it is not sorting listView descending (nothing happens btw). In arrayList are objects which this object has field named "rating". Here is a code: , Change your sorting comparator to this and you should be good to go:
Collections.sort(ratingSort, new Comparator<GifModel>() {

    public int compare(GifModel lhs, GifModel rhs) {
        if (lhs.getRating() < rhs.getRating())
            return -1;
        else if (lhs.getRating() > rhs.getRating())
            return 1;
        return 0;


java int comparation

Tag : java , By : user157064
Date : March 29 2020, 07:55 AM
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