Python beginner, strange output problem

hop of those help? im new to pragraming :) I got a problem with sytax error while making a guessing game. the problem is in (if Gender = boy or Boy), the equal(=) letter is a syntax error. Please help! , Write them like this:

if Gender in ('boy', 'Boy'):

if Gender in ('girl', 'Girl'):

if Gender in options

if Gender == 'boy' or Gender == 'something else'

This might help you I try to make a simple JSF2 application in Eclipse indigo. I have a very simple ManagedBean (call HelloBean.java) , Check that you have the Faces Servlet in your web.xml:

<servlet>
    <servlet-name>Faces Servlet</servlet-name>
    <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>/faces/*</url-pattern>
</servlet-mapping>

Any of those help input() returns a string. What you're checking is "-5" < 0, which is False.
Change your input statement to:

n = int(input("Number?"))

like below fixes the issue You can't do that with input() statements - it only works with print(). So print() can take any number of strings as an argument, but input() will only take one (and in recent versions of python will raise an error if you try to give it more than one - when I tried to run your code myself, I got a TypeError).
If you want to include name in the text of the input(), you'll need to either concatenate it:

input("I think you're being rather terse " + name + ". ")

input(f"I think you're being rather terse {name}. ")

around this issue As bruno said in his answer there are a few issues in your code, He already told about your issue with grid and how allocating to it in the function actually points the local scope version to the new grid and not the global scope one. He also covers how to resolve this.
The other issue you will have is that you have undertood that just doing new_grid = grid will mean that new_grid and grid point at the same list. So to prevent this you have correctly done new_grid = grid[:] as this will create a new list in memory and copy the data from the grid list. However thats a shallow copy, so you will create a new list object but copy all the list references inside your list. we can demonstrate this by doing a shallow copy of a list and then changing a value in the new list.

grid_size = 2
grid = [[0 for i in range(grid_size)] for j in range(grid_size)]
new_grid = grid[:]
new_grid[1][1] = "R"
print("grid:", grid)
print("newg:", new_grid)

#output#
grid: [[0, 0], [0, 'R']]
newg: [[0, 0], [0, 'R']]

from copy import deepcopy


def alive_neighbours(grid, r, c):
    differences = (0, -1, +1)
    cells_in_square = [(r + a, c + b) for a in differences for b in differences]
    total = 0
    for x,y in cells_in_square[1:]:
        try:
            if x >=0 and y>=0:
                total += grid[x][y]
        except IndexError as ie:
            pass #ignore index errors as at the edge of the grid
    return total


def next_gen(grid):
    new_grid = deepcopy(grid)
    for r in range(len(grid)):
        for c in range(len(grid)):
            neighbour = alive_neighbours(grid, r, c)
            if grid[r][c] == 1 and (neighbour > 3 or neighbour < 2):
                new_grid[r][c] = 0
            elif grid[r][c] == 0 and neighbour == 3:
                new_grid[r][c] = 1
    return new_grid


def printf(grid):
    for r in grid:
        for c in r:
            if c == 1:
                print("*", end=" ")
            else:
                print(" ", end=" ")
        print("")


grid_size = 50
grid = [[0 for i in range(grid_size)] for j in range(grid_size)]
grid[25][25] = 1
grid[26][26] = 1
grid[27][24] = 1
grid[27][25] = 1
grid[27][26] = 1
grid[49][49] = 1

while True:
    x = (input("press enter to see next grid: "))
    if x:
        break
    printf(grid)
    grid = next_gen(grid)

grid_size = 50
grid = [[0 for i in range(grid_size)] for j in range(grid_size)]
grid[25][25] = 1
grid[26][24] = 1
grid[26][25] = 1
grid[26][26] = 1
grid[27][24] = 1
grid[27][26] = 1
grid[28][25] = 1